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What is the exact value of sin^-1 (0) and how do you get that?

2 Answers

4 votes

Answer:

B.) 0

Explanation:

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User Matpol
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5 votes

Answer:

See Explanation

Explanation:


let \: y = { \sin}^( - 1) (0) \\ \\ \therefore \: \sin \: y = 0 \\ \\ \therefore \: \sin \: y = \sin \: 0 \degree\\( \because \: \sin \: 0 \degree= 0) \\ \\ \therefore \: y \: = 0 \degree \\ \implies \: { \sin}^( - 1) (0) = 0 \degree \\ \\ in \: the \: same \: way \\ \\ { \sin}^( - 1) (0) = 180 \degree \\ \\{ \sin}^( - 1) (0) = 360 \degree \\ \\

User Akhaku
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