The rectangular plot has a width of 22 meters and a length of 28 meters, as determined by solving the equation for the given area of 616 square meters, where the length is 6 meters more than the width.
Let's denote the width of the rectangular plot as w meters. According to the given information, the length is 6 meters more than the width, so the length is w + 6 meters.
The area A of a rectangle is given by the formula:
![\[ A = \text{length} * \text{width} \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/kqk0q7ns64rauoujbhd0tp8zjmbecwoxps.png)
In this case, we know that the area is 616 square meters:
![\[ 616 = (w + 6) * w](https://img.qammunity.org/2021/formulas/mathematics/high-school/k22uf8acpr4nprpkczjnt6oshq8aea9ksh.png)
Now, let's solve for w:
![\[ w^2 + 6w - 616 = 0 \]](https://img.qammunity.org/2021/formulas/mathematics/high-school/pv78o6bwwo3oh5mo7dxbs1ez9ip1dbtqfl.png)
We can factor this quadratic equation:
(w + 28)(w - 22) = 0
So, w = 22 or w = -28. Since the width cannot be negative, the width is 22 meters.
Therefore, the dimensions of the rectangular plot are:
- Width: 22 meters
- Length: 22 + 6 = 28 meters
The probable question may be:
The area of a rectangular plot of land is 616 square meters. If the length of the plot measures 6 m more than the width, what are its dimensions?