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How many formula units are there in 325 grams PbO2?

User Myabc
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Answer:

There are approximately 8.183 × 10²³ units of PbO₂ in 325 grams of PbO₂

Step-by-step explanation:

The given mass of PbO₂ = 325 grams

The molar mass of PbO₂ = 239.2 g/mol

The number of moles of PbO₂ in 325 grams of PbO₂ is given by the formula for the number of moles of a chemical compound in a given sample of the compound as follows;


The \ number \ of \ moles, n = (Mass \ of \ the \ substance)/(Molar \ mass \ of \ the \ substance)

For the given PbO₂ compound, in the question, we have;


The \ number \ of \ moles, n = (325 \ g)/(239.2 \ g/mole) \approx 1.36 \ moles

The number of units of PbO₂ in one mole is given by the Avogadro's number as follows;

The number of units of PbO₂ per mole = 6.023 × 10²³ units

The number of units of PbO₂,
U_(PbO_2) in 1.36 mole of PbO₂ is therefore;


U_(PbO_2) = 1.36 × 6.023 × 10²³ units ≈ 8.183 × 10²³ units of PbO₂

The number of units of PbO₂, in 1.36 mole of PbO₂ ≈ 8.183 × 10²³ units.

User Partial
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