Question

How many Sr2+ ions are present in 0.314 moles of Sr3(PO4)2?

Answer 1

5.67x10²³ ions

Step-by-step explanation:

By looking at the molecular formula, we can tell that there are three Sr²⁺ ions per Sr₃(PO₄)₂ molecule.

We convert Sr₃(PO₄)₂ moles into Sr₃(PO₄)₂ molecules by using Avogadro's number:

• 0.314 moles * 6.023x10²³ = 1.89x10²³ molecules

Finally we multiply that number by 3 in order to convert Sr₃(PO₄)₂ molecules to Sr²⁺ ions:

• 1.89x10²³ * 3 = 5.67x10²³ ions.