Question

The perimeter of a rectangular building is 1200 feet. The width of the building is 2 feet less than three times the length. What is the width of the building?

Answer 1

Given:

The perimeter of a rectangular building is 1200 feet.

The width of the building is 2 feet less than three times the length.

To find:

Width of the building.

Solution:

Let length of the building be x.

Then, width = 3x-2

We know that,

`Perimeter=2(length +width)`

`1200=2(x+3x-2)`

`1200=2(4x-2)`

`1200=8x-4`

Add 4 on both sides

`1204=8x`

Divide both sides by 8.

`(1204)/(8)=x`

`150.5=x`

Now,

`Width=3x-2`

`Width=3(150.5)-2`

`Width=451.5-2`

`Width=449.5`

Therefore, the width of the building is 449.5 feet.