Question

What is the molarity of a solution in which 102 grams of aluminum oxide, Al2O3, is

dissolved in 500 mL of solution?

Answer 1

2.00 M

Step-by-step explanation:

The formula mass of aluminum oxide is 2(27)+3(16)=102 g/mol.

So, there is 1 mole of solute in 500 mL=0.5 L of solution

Now, we can use the equation molarity = (moles of solute)/(liters of solution)

• molarity = 1/0.5 = 2.00 M