![\large\bold{\underline{\underline{Given:-}}}](https://img.qammunity.org/2021/formulas/physics/high-school/mkrwbh6lln3k9zayjiu9yf0ern9gnfz9c6.png)
= 8kg
= 4kg
g = 10m/s²
![\large\bold{\underline{\underline{To \: Find:-}}}](https://img.qammunity.org/2021/formulas/physics/high-school/j4t0jbnkxgkvqafhvvdq7e61ml7p5hh4a8.png)
→Acceleration of block
→Tension in strings
![\large\bold{\underline{\underline{Solution:-}}}](https://img.qammunity.org/2021/formulas/physics/high-school/i0kswtpr0gmf78emjg48vmxg897jlex3ys.png)
Let, the two equation will be ,
8g - T = 8a ..... Equation no (1)
T - 4g = 4a ..... Equation no (2)
Putting the value of equation no (1) and (2) we get,
4g = 12a
4 × 10 = 12a
40 = 12a
a =
a =
![(10)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s78bftcylqemadbofpp9mvzxhiwe7ty5oz.png)
Again, we have to putting the value of a in the equation no (2) we get,
T - 4g = 4 ×
![(10)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s78bftcylqemadbofpp9mvzxhiwe7ty5oz.png)
T - 4 × 10 = 4 ×
![(10)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s78bftcylqemadbofpp9mvzxhiwe7ty5oz.png)
T - 40 =
![(40)/(3)](https://img.qammunity.org/2021/formulas/physics/high-school/cn3ud5qq3h53wdywekusf4zlnkhs0hw8hh.png)
T =
+ 40
T =
![(40 + 120)/(3)](https://img.qammunity.org/2021/formulas/physics/high-school/lqqmguwltinq6v9ajvaait355bq17t3me7.png)
T =
N
Acceleration of block =
m/s².
And, Tension in strings =
N