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The average height of an apple tree is 4.00 m how long will it take for an apple falling from that height to reach the ground given G equals -9.8 m a second squared

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Answer:

The time taken for the apple to reach the ground is 0.9 s

Step-by-step explanation:

Given;

height of the apple tree, h = 4 m

acceleration due to gravity, g = 9.8 m/s²

The time taken for the apple to reach the ground is given by;


h = (1)/(2)gt^2\\\\t^2 = (2h)/(g)\\\\t = \sqrt{(2h)/(g)}\\\\t = \sqrt{(2*4)/(9.8)}\\\\t = 0.9 \ s

Therefore, the time taken for the apple to reach the ground is 0.9 s

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