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At 96° F the saturation density of air is 0.04 kg/m3. If the weather report says the relative humidity is 90 % when the temperature is 96°F, the humidity is

User Ferrix
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3 votes

Answer:

The value is
H = 0.036 \ kg/m^3

Step-by-step explanation:

From the question we are told that

The saturation density of air is
\rho = 0.04 \ kg/m^3

The temperature for this saturation density to occur
T_s = 96^o F

The relative humidity at this temperature is
R_h = 90\% = 0.90

Generally the relative humidity is mathematically represented as


R_H = (H)/(\rho)

Here H represents humidity

=>
0.90 = (H)/(0.04)

=>
H = 0.90 * 0.04

=>
H = 0.036 \ kg/m^3

User Qtmfld
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