Question

A coiled telephone cord forms a spiral with 65.0 turns, a diameter of 1.30 cm, and an unstretched length of 65.5 cm. Determine the inductance of one conductor in the unstretched cord.

Answer 1

`L=1.07\ \mu H`

Step-by-step explanation:

Given that,

No of turns in a coiled telephone cord is 65

The diameter of the coil, d = 1.3 cm = 0.013 m

Radius, r = 0.0065 m

Unstretched length of the coil, l = 65.5 cm = 0.655 m

We need to find the inductance of one conductor in the unstretched cord. The formula for the inductance is given by :

`L=(\mu_oN^2 A)/(l)\\\\L=(4\pi * 10^(-7)* (65)^2* \pi (0.0065)^2)/(0.655 )\\\\L=1.07* 10^(-6)\ H\\\\L=1.07\ \mu H`

So, the inductance of one conductor in the unstretched cord is
`1.07\ \mu H`.