Question

What is the final concentration of HCl in a solution prepared by addition of 922.0 mL of 4.73 M HCl to 549.0 mL of 2.03 M HCl

Answer 1

the final concentration of HCl is 3.72 M

Step-by-step explanation:

Given that;

V1 = 922.0 mL, M1 = 4.73 M

V2 = 549.0 mL, M2 = 2.03 M

so final concentration of HCL

= (( M1V1) + (M2V2)) / (V1 + V2)

(( 4.73 × 922.0)) + (2.03 × 549.0)) / (922.0 + 549.0)

= 5475.53 / 1471.0

= 3.7223 ≈ 3.72 M

Therefore the final concentration of HCl is 3.72 M