Question

The modulus of elasticity for a ceramic material having 4.7 vol% porosity is 317 GPa. (a) Calculate the modulus of elasticity (in GPa) for the nonporous material.

Answer 1

The answer is below

Step-by-step explanation:

a) Given that the modulus of elasticity (E) = 317 GPa, to find the modulus of elasticity (in GPa) for the nonporous material (
`E_o`), we use the formula:

`E_0=(E)/(1-1.9P+0.9P^2)\\\\where\ P=4.7\%=0.047,hence:\\\\ E_0=(317)/(1-1.9(0.047)+0.9(0.047)^2)\\\\E_0=347.3\ GPa`

b) If the porosity P = 11.1%, then the modulus of elasticity is:

`E=E_0(1-1.9P+0.9P^2)=347.3(1-1.9(0.111)+0.9(0.111)^2)=278\ GPa`