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A helicopter is moving at a horizontal speed when it drops a container so it lands with a range of 80 meters. If the helicopter is 37 meters from the ground what is its horizontal speed? (10 points)

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Answer:

The horizontal speed is approximately 29 m/s.

Step-by-step explanation:

Given that; range = 80 meters, height = 37 meters.

The horizontal speed can be determined by:

R = U
\sqrt{(2H)/(g) }

Where R is the range, U is the velocity of the object, H is the height and g is the acceleration due to gravity (9.8 m/
s^(2)).

So that:

80 = U
\sqrt{(2*37)/(9.8) }

= U
\sqrt{(74)/(9.8) }

= U
√(7.55102)

80 = 2.747912U

⇒ U =
(80)/(2.747912)

= 29.1130

U ≅ 29 m/s

The horizontal speed is approximately 29 m/s.

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