Question

An automobile accelerates uniformly from a speed of 60 km/hr (16.67 m/s) to a speed of 80 km/hr (22.2 m/s) in 5 s. Determine the acceleration of the car and the distance traveled in this 5 sec interval.

Answer 1

The acceleration is
`1.106\ m/s^2` and the distance covered is 97.17 m.

Step-by-step explanation:

Given that,

Initial speed of an automobile, u = 60 km/hr = 16.67 m/s

Final speed of an automobile, v = 80 km/hr = 22.2 m/s

Time, t = 5 s

We need to find the acceleration of the car and the distance traveled in this 5 sec interval. Let a is the acceleration. Using the definition of acceleration as :

`a=(v-u)/(t)\\\\a=(22.2-16.67)/(5)\\\\a=1.106\ m/s^2`

Let d is the distance covered. Using the third equation of motion to find it as follows :

`v^2-u^2=2as\\\\s=(v^2-u^2)/(2a)\\\\s=((22.2)^2-(16.67)^2)/(2* 1.106)\\\\s=97.17\ m`

So, the acceleration is
`1.106\ m/s^2` and the distance covered is 97.17 m.