Question

If (he)={(0,1),(2,3),(-4,1)}, find h^-1(x)

Answer 1

The given function is

`h(x) = \{ (0,1), (2,3), (-4, 1) \}`

The inverse function is

`h^(-1)(x) = \{ (1,0), (3,2), (1,-4)\}`

To get the inverse, we swap each x and y coordinate.

The rule is
`(x,y) \to (y,x)`

So that's why the point (0,1) becomes (1,0) for instance.