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Three numbers are in the ratio 1:3:5 and their sum is 270. find the largest number.

User Rolandow
by
7.8k points

2 Answers

11 votes

Answer:

150

Explanation:

Let :

⇒ The numbers can be denoted as x, 3x, and 5x

=============================================================

Solving :

⇒ It mentions their sum is 270

⇒ x + 3x + 5x = 270

⇒ 9x = 270

⇒ x = 30

=============================================================

Largest number :

⇒ 5x

⇒ 5(30)

150

User Phagun Baya
by
7.7k points
1 vote

Answer :

  • Largest number is 150.

Step by step explaination :

Here we have been given with the ratio of three numbers that is 1 : 3 : 5. So let us assume a common factor for them , we are assuming it as y.

Therefore,

  • First number = 1 → 1 × y = 1y
  • Second number = 3 → 3 × y = 3y
  • Third number = 5 → 5 × y = 5y

Sum of them is 270 :

>> 1y + 3y + 5y = 270

>> 4y + 5y = 270

>> 9y = 270

>> y = 270 / 9

>> y = 90 / 3

>> y = 30

Henceforth, value of y is 30.

Finding out first number :-

>> First number = 1y

>> First number = 1 × 30

>> First number = 30

★ Finding out second number :-

>> Second number = 3y

>> Second number = 3 × 30

>> Second number = 90

★ Finding out third number :-

>> Third number = 5y

>> Third number = 5 × 30

>> Third number = 150

User Aleksej Vasinov
by
8.6k points

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