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What is the location of the image of P(−8, 1) after a counterclockwise rotation of 90° about (−2, 6) ?

User Guy Cothal
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1 Answer

1 vote

Answer:

(3, 0)

Explanation:

Given:

  • Image: P = (-8, 1)
  • Center of rotation: (-2, 6)

Rotation rule for -90°: (x, y) → (y, -x)

As the center of rotation is not the origin, we cannot simply apply the above rule.

To rotate an image around a point other than the origin:

1. Subtract each point of the image from the point of rotation:

⇒ Point of rotation - point of image

⇒ (-2, 6) - P = (-2, 6) - (-8, 1)

= (6, 5)

2. Rotate this about the origin by applying the rotation rule:

⇒ (x, y) → (y, -x)

⇒ (6, 5) → (5, -6)

Add the point of rotation to each rotated point of the image:

⇒ (5, -6) + (-2, 6) = (3, 0)

Therefore, the location of the image of P (-8, 1) after a counterclockwise rotation of 90° about (-2, 6) is (3, 0).

What is the location of the image of P(−8, 1) after a counterclockwise rotation of-example-1
User JanLauGe
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