Answer:
2P (s) + 5PCl₂ (g) → 2PCl₅ (s)
Step-by-step explanation:
There are 2 chlorine atoms on the reactant side and 5 chlorine atoms on the product side.
Hence, multiply the left chlorine molecule by 5 and right compound by 2.
⇒ P (s) + 5 × Cl₂ (g) → 2 × PCl₅
⇒ P (s) + 5Cl₂ (g) → 2PCl₅ (s)
But, now we see that there is 1 phosphorus atom on the reactant side and 2 phosphorus atoms on the right.
So, multiply the left phosphorus atom by 2 to balance.
⇒ 2 × P (s) + 5PCl₂ (g) → 2PCl₅ (s)
⇒ 2P (s) + 5PCl₂ (g) → 2PCl₅ (s)