Question

1. A student is titrating 0.61 M KOH with 14.5 mL of 0.47 M H2SO4

ii. What volume of 0.61 M KOH is needed to titrate the H2SO4?
ii. What mass of water can be produced if 131 g of the H2SO4 solution react with 225 mL
of 0.61 M KOH?


Can someone help me with this?

Answer 1

M KOH = 0.61 M

V H2SO4 = 14.5 ml

M H2SO4 = 0.47 M

Volume KOH = ?

( V . M . valensi) KOH = (V . M . valensi) H2SO4

V . 0.61 . 1 = 0.47 . 14.5 . 2

V KOH = (0.47 . 14.5 . 2) / 0.61

V KOH = 22.34 ml

see more the answer at the pic