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If y varies directly with x and y= 12 when x= 16, what is the value of x when y= 5?

User Khoi
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1 Answer

3 votes

Answer:


x = 6 (2)/(3)

Explanation:

Since y varies directly with x,

y= kx, where k is a constant.

① Find the value of the constant k.

When y=12, x= 16,

12= k(16)

16k= 12


k = (12)/(16) \\ k = (3)/(4)

②Substitute the value of k back into the equation:


y = (3)/(4) x

③ Find value of x when y=5.

When y=5,


5 = (3)/(4) x \\ x = 5 / (3)/(4) \\ x = 5 * (4)/(3) \\ x = (20)/(3) \\ x = 6 (2)/(3)

User Jim Speaker
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