Question

How many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 340 K?

Answer 1

9.9 moles

Step-by-step explanation:

What we know:

P = 2.3 atm V = 120 L

R= .0821 L atm/K mol T= 340 K

What we're looking for: n = ?

2.3 atm ( 120 L) = n (.0821 L atm/K mol) (340 K)

2.3 ( 120 ) = n (.0821 / mol) (340)

276 = n (27.914 / mol )

9.9 = n / mol

9.9 mol = n