Question

A motorcycle starts at rest and moves a distance of 460m .

If it has constant acceleration of 4m55 m/s2 what is its final velocity

Answer 1

The final velocity of the motorcycle is 64.7 m/s

Note: Since the value for the acceleration of the motorcycle is not clear, it is assumed to be 4.55 m/s² in the calculation

Step-by-step explanation:

Using the equation of motion that contains all the given values in the question: v² = u² + 2as

where v is final velocity; u is initial velocity; a is acceleration; s is horizontal distance

v = ?, u = 0 (since the motorcycle starts from rest), a = 4.55 m/s², s = 460 m

v² = 0² + 2 * 4.55 * 460

v² = 4186

take square root of both sides

v = 64.7 m/s

Therefore, the final velocity of the motorcycle is 64.7 m/s