Question

Peggy decided to sell brownies and cookies to raise

money for her basketball uniform. She sold
brownies for $3.00 and cookies for $2.50. If she
sold 3 fewer cookies than brownies and collected
$218 in all, then how many brownies did she sell?
Write and solve an equation (or a system of
equations) to find your solution.

Answer 1

Peggy sold 41 brownies.

Explanation:

She sold three more brownies. 1 brownie cost $3.00, so 3 brownies cost $9.00 because 3×$3.00.

$218-$9 = $209

Figure out the cost of 1 cookie and 1 brownie: $3.00+$2.50=$5.50

$209÷$5.50=38

This means that Peggy sold 38 cookies.

Since she sold 3 more brownies than cookies, add 3 to 38.

3+38=41

So, Peggy sold 41 brownies.