Question

How many oxygen atoms are present in 22.6 grams of sulfur trioxide (SO,)?
(Show work)

Answer 1

Well,

3

×

N

A

oxygen atoms..

Step-by-step explanation:

Where

N

A

≡

Avogadro's number

≡

6.022

×

10

23

⋅

m

o

l

−

1

.

And so if wl1

oxygen atoms...

i.e.

18.066×

1023

⋅

oxygen atoms..