Answer:
m∠ABC = 60°
The distance from C to AB = 3 cm
The distance from l to AB = 1.5 cm
Explanation:
The median of ΔABC = BM
The length of MC = 3 cm
Type of triangle given as ΔBMC = Equilateral triangle
Line MN is parallel to AB and passes through M intersecting CB at N
Given that BM is a median, we have;
MC = AM = 3 cm
BM = MC = CB = 3 cm, from ΔBMC = Equilateral triangle
CN = NB by midpoint theorem
∴ CB = CN + NB = 2·CN = 3 cm
The distance from C to AB = CB = 3 cm
The distance from C to AB = 3 cm
CN = 3/2 = 1.5
CN = NB = 1.5
The distance from l to AB = CN = 1.5 cm
The distance from l to AB = 1.5 cm
m∠ABC = m∠BMC = m∠MBC = 60° Interior angles of an equilateral triangle.
m∠ABC = 60°