Question

40.0 grams of liquid at its boiling point is

changed to vapor by the addition of 12800
joules of heat. What is the heat of
vaporization of the substance?

Answer 1

320J/g

Step-by-step explanation:

Given parameters:

Mass of the liquid = 40g

Amount of heat added = 12800J

Unknown:

The heat of vaporization = ?

Solution:

The heat of vaporization can be related to heat added by the expression below;

H = mL

H is the heat added

m is the mass

L is the heat of vaporization

Insert the parameters and solve;

12800 = 40 x L

L =
`(12800)/(40)` = 320J/g