Question

The temperature of a sample of gas in a steel tank at 0.30 ATM at 25 Celsius if the pressure W20.59 ATM what would be the final temperature inside the tank in kelvin

Answer 1

The final temperature : 313.06 °C

Further explanation

Gay Lussac's Law

When the volume is not changed, the gas pressure is proportional to its absolute temperature

`(P_1)/(T_1)=(P_2)/(T_2)`

P1=0.3 atm

T1=25 + 273=298 K

P2=0.59 atm

`\tt (0.3)/(298)=(0.59)/(T_2)\\\\T_2=586.06=313.06~^oC`