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1 vote
Find the smallest natural number that is a multiple of 45 and where all of its digits are zeros and ones.

1 Answer

1 vote

Answer:

1111111110

Explanation:

45 is 9, and 5.

9 divisibility rule: Digits have to add up to 9.

We know this has to be 1's and 0's.

So there has to be 9 1's.

111111111.

5 divisibility rule: Last digit has to be 0 or 5.

1111111110 will be our final answer.

Wait- let's check if it's divisible. Using a calculator, this determines it does work.

Enjoy.

User John Lawrence
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