Question 1

7 1/6 = 5 2/5 + p

p = ???

Question 2

hope this helps ??!!

Question 3

$\huge\textbf{Hey there!}$

$\mathbf{7(1)/(6) = 5(2)/(5) + p}$

$\rightarrow\mathbf{7 (1)/(6) = 5(2)/(5) + p}$

$\mathbf{\rightarrow p + 5(2)/(5)= 7(1)/(6)}$

$\mathbf{\rightarrow {p + (27)/(5)=(43)/(6)}}$

$\text{SUBTRACT }\rm{(27)/(5)}\text{ to BOTH SIDES}$

$\mathbf{p + (27)/(5) - (27)/(5) = (43)/(6)- (27)/(5)}$

$\text{CANCEL out: }\rm{(27)/(5) - (27)/(5)}\text{ because it gives you 0}$

$\text{KEEP: }\rm{(43)/(6) - (27)/(5)}\text{ because it help solve for the p-value}$

$\text{NEW EQUATION: }\rm{p = (43)/(6) - (27)/(5)}$

$\large\textsf{SIMPLIFY IT!}$

$\mathbf{p = (53)/(30) \approx p = 1(23)/(30)}$

$\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1(23)/(30)}}}}\huge\checkmark$

$\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}$

~
$\frak{Amphitrite1040:)}$

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