I NEED HELP WITH THIS PLZ HELP ME WITH MATH! I"M GIVING 20 points for someone who answers it. PLZ HELP ME WITH MATH!

Question

asked Oct 13, 2021 156k views

1 Answer

Rody Oldenhuis · Answer 1 · 2021-10-16T19:21:19+0000

Answer:

X^8 / 256y^20

Explanation:

First to make your life easier with this problem reduce the fraction 5/20 = 1/4

x^3/x = x^3-1= x^2

Then you apply the outer exponent

X^2*4 = X^8

4^4= 256

y^5*4 = y^20

X^8 / 256y^20