Question

Three numbers are in the ratio 3:4:5. If the sum of their cubes is 216000, find the largest of these three numbers.

Answer 1

50

Explanation:

Let the numbers be 3x, 4x, 5x

(3x)^3 + (4x)^3 + (5x)^3 = 216000

27x^3 + 64x^3 + 125x^3 = 216000

216x^3 = 216000

x^3 = 1000

x = 10

5x = 5(10) = 50

Answer: 50