Answer:
about 1.01 °C per hour
Explanation:
We assume the intended temperature function is ...
t(h) = 18 +4·sin(π/12(h -8))
We are asked for the rate of change when h=9.
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derivative
The rate of change of temperature with respect to time is the derivative of t(h) with respect to h.
t'(h) = 4(π/12)cos(π/12(h -8)) = π/3·cos(π/12(h -8))
at 9 am
For h = 9 hours after midnight, the rate of change is ...
t'(9) = π/3·cos(π/12(9 -8)) = π/3·cos(π/12) ≈ (3.14159)(0.965926)/3
t'(9) ≈ 1.01152
The rate of change of temperature at 9 a.m. is about 1.01 °C/hour.