Question

1. A ball rolls off of a table with a speed of 3.2 m/s. The table is 1.6 m high.

a) When does the ball hit the ground? (time)
b) How far away from the base of the table does the ball travel?
c) With what vertical speed does the ball hit the floor?

Answer 1

Step-by-step explanation:

for vertical displacement h = 1.6 , let time taken be t , initial vertical velocity = 0

h = ut + 1/2 g t²

= 1/2 g t²

1.6 = .5 x 9.8 x t²

t² = .3265

t = .57 s

b )

velocity in horizontal direction = 3.2 m /s

horizontal displacement

= 3.2 x .57 = 1.82 m

c )

for vertical movement

v = u + gt

= 0 + 9.8 x .57

= 5.58 m /s