Question

One number is 4 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 526 ​, find the numbers.

The three numbers are nothing. ________ (Use a comma to separate answers as​ needed.)

Answer 1

The three numbers are 71, 284, 171

Step-by-step explanation:

Let n = the first number

4n = Second number

100 + n = Third number

Equation :

n + 4n + 100 + n = 526 Combine liked terms

6n + 100 = 526

- 100 - 100 Subtract 100 from both sides

6n = 426

÷ 6 ÷ 6 Divide 6 from both sides

n = 71

Plug in :

4(71) = 284

100 + 71 = 171