Register

M = 30.3kg M = 40.17kg 9 R = 0.5m G = 6. 67x10^11 F ?​

M = 30.3kg M = 40.17kg 9 R = 0.5m G = 6. 67x10^11 F ?​
233k views
4 votes
M = 30.3kg
M = 40.17kg 9
R = 0.5m
G = 6. 67x10^11
F ?​

User Jovica
by
7.9k points

1 Answer

0 votes

Answer:

m¹=30.3kg

m²=40.17kg

R=0.5m

G=6.67*10¹¹

F=Gm¹m²/R²

=160.68

User Rawburner
by
7.8k points
← Prev Question Next Question →

Related questions

User Andora
asked Jul 11, 2024 97.6k views
What is the force of friction on a moving mass of 17kg, if the coefficient of friction is u=0.3?
Andora asked Jul 11, 2024
by Andora
7.6k points
1 answer
1 vote
97.6k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

At sea level, water boils at 100 degrees celcius and methane  boiled at -161 degrees celcius. Which of these substances has a stronger force of attraction between its particles? Explain your answer
Physical properties of minerals graphic organizer
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?
Link Copied!