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What is the percent composition of all the elements of sucrose, C12, H22 and O11?please be specific..​

User Bobu
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1 Answer

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There are completely ( 12 + 22 + 11 = 45 ) elements .

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(( C )) percentage :


(12)/(45) * 100 = (4)/(15) * 100 = 26.666 \: \: percent \\

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(( H )) percentage :


(22)/(45) * 100 = 48.888 \: \: percent \\

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(( O )) percentage :


(11)/(45) * 100 = 24.444 \: \: percetage \\

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User NotSoShabby
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