Answer:
2.4 minutes ; 0.8333 ; 8.4 minutes ; 14.4 minutes
Step-by-step explanation:
Given that:
Number of agents (n) = 3
Mean calls per hour (λ) = 25calls/hr
Average Number of calls in queue (Q) =3.5
Service time (E) = 6 minutes ;
Hence, mean service rate (μ) = 60/ 6 = 10 calls/hr
A.) The inter-arrival time :
1 /λ = 1 / 25 = 0.04 hours = (0.04 * 60) = 2.4 mins
The utilization of the system :
Mean calls per hour /(number of agents * mean service rate)
λ / (n * μ) = 25/ (3 * 10)
= 25 / 30
= 0.8333
Queue waiting time :
Q / λ
= 3. 5 * 0.04
= 0.14 hour = (0.14 * 60) = 8.4 minutes
System waiting time :
Queue waiting time + service time
8.4 minutes + 6 minutes = 14.4 minutes