Answer:
The probability that 24 or more from this sample will be female is 0.2643.
Explanation:
Define X as the number of female students.
The random variable X follows a Binomial distribution with parameters n = 40 and p = 0.55.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
1. np ≥ 10
2. n(1 - p) ≥ 10
Check the conditions as follows:
![np=40* 0.55=22>10\\\\n(1-p)=40* (1-0.55)18>10](https://img.qammunity.org/2021/formulas/mathematics/college/atpza5741t7dnv86uue2x6vnnh574d8fm1.png)
Thus, a Normal approximation to binomial can be applied.
So, X follows normal distribution with mean and standard deviation:
![\mu=np=40* 0.55=22\\\\\sigma=√(np(1-p))=√(40* 0.55* (1-0.55))=3.15](https://img.qammunity.org/2021/formulas/mathematics/college/wuche6ewmsswomyt3sx78l2kt8gr6o1yxu.png)
Compute the probability that 24 or more from this sample will be female as follows:
![P(X\geq 24)=P((X-\mu)/(\sigma)>(24-22)/(3.15))\\\\=P(Z>0.63)\\\\=1-P(Z<0.63)\\\\=1-0.7357\\\\=0.2643](https://img.qammunity.org/2021/formulas/mathematics/college/vconhaqaf2440ov9pj3a6f3iyssgxud3mu.png)
Thus, the probability that 24 or more from this sample will be female is 0.2643.