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An EWMA control chart uses λ = 0.5. What is the value of L such that the control limits of this EWMA control chart in the steady state have the same width with a 3σ X_bar control chart?

User Paddington
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1 Answer

2 votes

Answer:

5.199

Explanation:

From the information provided;

We know that λ = 0.5.

However, the control limits for a steady-state EMWA control chart is:


\mu_o \pm L \sigma \sqrt{(\lambda )/((2-\lambda )n)}

where;


UCL = \mu_o + L \sigma \sqrt{(\lambda )/((2-\lambda )n)}


LCL = \mu_o- L \sigma \sqrt{(\lambda )/((2-\lambda )n)}

Given that the data is chosen from an individual sample;

Then; we can express the width as:


L \sigma \sqrt{(\lambda)/((2-\lambda))}= 3 \sigma


L \sqrt{(\lambda)/((2-\lambda))}= 3


L \sqrt{(0.5)/((2-0.5))}= 3


L \sqrt{(0.5)/((1.5))}= 3


L √(0.333)= 3


L* 0.577= 3


L=( 3 )/(0.577)

L = 5.199

User Vinu
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