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Consider random samples of size 900 from a population with proportion 0.65 . Find the standard error of the distribution of sample proportions.

User Morchul
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1 Answer

4 votes

Answer:

The value is
\sigma_(p) = 0.022

Explanation:

From the question we are told that

The sample size is n = 900

The population proportion is
p = 0.65

Generally the standard error of the distribution of sample proportion is mathematically represented as


\sigma_(p) = \sqrt{( p(1 - p))/( n) }

=>
\sigma_(p) = \sqrt{( 0.65 (1 - 0.65 ))/( 900) }

=>
\sigma_(p) = 0.022

User Joi
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