Question

18% of all US residents have traveled to Canada, 9% to Mexico, and 4% to both. What is the probability that a US resident chosen at random has a. traveled to Canada or Mexico?

Answer 1

`P(Canada\ or\ Mexico)= 23\%`

Explanation:

Given

`P(Canada) = 18\%`

`P(Mexico) = 9\%`

`P(Both) = 4\%`

Required

Determine
`P(Canada\ or\ Mexico)`

In probability:

`P(A\ or\ B) = P(A) + P(B) - P(Both)`

In this case:

`P(Canada\ or\ Mexico)= P(Canada) + P(Mexico) - P(Both)`

Substitute values:

`P(Canada\ or\ Mexico)= 18\% + 9\% - 4\%`

`P(Canada\ or\ Mexico)= 23\%`

Hence, the required probability is 23%