18% of all US residents have traveled to Canada, 9% to Mexico, and 4% to both. What is the probability that a US resident chosen at random has a. traveled to Canada or Mexico?

Question

asked Feb 15, 2021 38.0k views

1 Answer

GuiDocs · Answer 1 · 2021-02-22T07:15:26+0000

Answer:

$P(Canada\ or\ Mexico)= 23\%$

Explanation:

Given

$P(Canada) = 18\%$

$P(Mexico) = 9\%$

$P(Both) = 4\%$

Required

Determine
$P(Canada\ or\ Mexico)$

In probability:

$P(A\ or\ B) = P(A) + P(B) - P(Both)$

In this case:

$P(Canada\ or\ Mexico)= P(Canada) + P(Mexico) - P(Both)$

Substitute values:

$P(Canada\ or\ Mexico)= 18\% + 9\% - 4\%$

$P(Canada\ or\ Mexico)= 23\%$

Hence, the required probability is 23%