Question

A chemist adds 255.0mL of a 1.27M sodium carbonate Na2CO3 solution to a reaction flask. Calculate the mass in grams of sodium carbonate the chemist has added to the flask.

Answer 1

Answer: The mass in grams of sodium carbonate is 34.3 g

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml

moles of
`Na_2CO_3` =
`\frac{\text {given mass}}{\text {Molar mass}}=(xg)/(106g/mol)`

Now put all the given values in the formula of molarity, we get

`1.27=(xg* 1000)/(106g/mol* 255.0 ml)`

`x=34.3g`

Therefore, the mass in grams of sodium carbonate is 34.3 g