Answer:
Explanation:
If the impedance is related to the voltage and the current by the formula V = IZ where;
V is the voltage
I is the current
Z is the impedance
Given
I = 0.4+3i
V = 0.3-2i
Voltage V = (0.4+3i)(0.3-2i)
V = 0.4(0.3)-0.8i+0.9i-6i²
V = 0.12+0.1i -6i²
Since i² = -1
V = 0.12+0.1i-6(-1)
V = 0.12+0.1i+6
V = 6.12+0.1i.
Hence the impedance is 6.12+0.1i