Answer:
f(x)= -5
Explanation:
Determine the types of roots for quadratic function f(x)= 2x^2 + x - 5 when f(x)= 0. Thus, sketch the graph generally at the x-axis
First, rewrite the equation.
f(x)= 2x^2 + x - 5 Then, subsitute the variables to ZERO (0).
f(0)= 2(0)^2 + 0 - 5
Zero raised to any number is zero.
Remove the zero before -5 because it's unecessary.
f(0)= 2(0) - 5
f(0)= 0 - 5
SIMPLIFY- The final answer is -5