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Fast pls? evaluate sin30 + tan45 - cosec60 / sin30 + cos45 + cot45

User Searsaw
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1 Answer

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( \sin(30) + \tan(45) - \csc(60) )/( \sin(30) + \cos(45) + \cot(45) ) = \\


( (1)/(2) + 1 - (1)/( (1)/(2) ) )/( (1)/(2) + ( √(2) )/(2) + 1 ) = \\


( (1)/(2) + (2)/(2) - 2 )/( (1)/(2) + ( √(2) )/(2) + (2)/(2) ) = \\


( (3)/(2) - (4)/(2) )/( (3 + √(5) )/(2) ) = \\


( - (1)/(2) )/( (3 + √(2) )/(2) ) = \\


- (1)/(3 + √(2) ) \\

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User Dirtydanee
by
7.2k points
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