1 Answer

Dirtydanee · Answer 1 · 2021-07-29T20:50:21+0000

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$( \sin(30) + \tan(45) - \csc(60) )/( \sin(30) + \cos(45) + \cot(45) ) = \\$

$( (1)/(2) + 1 - (1)/( (1)/(2) ) )/( (1)/(2) + ( √(2) )/(2) + 1 ) = \\$

$( (1)/(2) + (2)/(2) - 2 )/( (1)/(2) + ( √(2) )/(2) + (2)/(2) ) = \\$

$( (3)/(2) - (4)/(2) )/( (3 + √(5) )/(2) ) = \\$

$( - (1)/(2) )/( (3 + √(2) )/(2) ) = \\$

$- (1)/(3 + √(2) ) \\$

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