Question

A 75N force is applied to a 15kg box. If the box

accelerates at a rate of 3 m/s?, determine the coefficient
of kinetic friction.

Answer 1

The coefficient of kinetic friction is 0.51.

Step-by-step explanation:

Given that,

Applied force, F = 75 N

Mass of a box, m = 15 kg

The acceleration of the box is 3 m/s²

We need to find the coefficient of kinetic friction. It is given by the formula as follows :

`F=\mu_k F_N`

Where,

`F_N=mg`, is the normal force

`\mu_k=(F)/(mg)\\\\\mu_k=(75)/(15* 9.8)\\\\\mu_k=0.51`

So, the coefficient of kinetic friction is 0.51.