Question

A graduated cylinder has 20 ml (cm3) of water placed in it. An irregularly shaped rock is then dropped in the graduated cylinder and the volume of the rock and water in the cylinder now reads 30 ml (cm3). The mass of the rock dropped into the graduated cylinder is 23 grams.

a.) Find the volume of the rock dropped into the graduated cylinder.
b.) Find the density of the rock dropped into the graduated cylinder.

Answer 1

Volume = 10 cm3

Density = 2.3g/cm3

Step-by-step explanation:

volume:

30ml - 20ml = 10ml = 10cm3

density:

density = mass/volume

23/10

2.3g/cm3

Answer 2

`\boxed {\boxed {\sf v=10 \ mL \ and \ d=2.3 \ g/mL}}`

Step-by-step explanation:

Answer:

Explanation:

A. Volume

The volume was found using water displacement. Subtract the initial volume from the final volume.

`final \ volume - initial \ volume`

The graduated cylinder had 20 milliliters of water (initial volume).

After the rock was added, the graduated cylinder read 30 milliliters (final volume).

Substitute the values in and subtract.

`30 \ mL- 20 \ mL`

`10 \ mL`

The volume of the rock is 10 milliliters.

B. Density

Density can be found by dividing the mass by the volume.

`d=(m)/(v)`

The mass of the rock is 23 grams. We just found the volume of 10 milliliters.

`m= 23 \ g\\d= 10 \ mL`

Substitute the values in and divide.

`d=(23 \ g)/(10 \ mL)`

`d= 2.3 \ g/mL`

The density of the rock is 2.3 grams per milliliter.