Question

An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object

Answer 1

`\boxed {\boxed {\sf a=42.8 \ m/s^2}}`

Step-by-step explanation:

Acceleration can be found by dividing the change in velocity by the time.

`a=(v-u)/(t)` (v is the final velocity, u is the initial velocity, t is the time).

The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:

`v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s`

Substitute the values into the formula.

`a=(236 \ m/s - 22 \ m/s)/(5 \ s)`

Subtract in the numerator.

• 236 m/s-22 m/s=214 m/s

`a=(214 \ m/s)/(5 \ s)`

Divide.

`a=42.8 \ m/s^2`

The acceleration of the object is 42.8 meters per square second.