Answer:
p∴q⟹p therefore q
p⟺q⟹p if and only if q
p∧q⟹p and q
p∨q⟹p or q
p∧∼q⟹p and not q
q⟹∼p⟹if q then not p
∼p⟹q⟹if not p then q
Answer: Go in a pattern example p and q like that then you get answer
Step-by-step explanation: pls mark me branist
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