Question

Calculate the mass of

Carbon monoxide having
the same number of
oxygen atompresent in
88 g of carbon dioxide

​

Answer 1

The mass of CO = 112 g

Further explanation

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³ particles

Moles can also be determined from the amount of substance mass and its molar mass

number of atoms in 88 g CO₂ :

`\tt mass~O=(2.16)/(44)* 88\\\\mol~O=(mass~O)/(Ar~O)=(2.16.88)/(44.16)=4\\\\number~of~atoms=4* 6.02* 10^(23)`

number of atoms in CO :

`\tt mass~O=(16)/(28)* mass~CO`

`\tt mol~O=(mass~O)/(Ar~O)=(16.mass~CO)/(28.16)=(mass~CO)/(28)`

`\tt number~of~atoms=(mass~CO)/(28)* 6.02* 10^(23)`

number of atoms in CO₂ = number of atoms in CO :

`\tt 4* 6.02* 10^(23)=(mass~CO)/(28)* 6.02* 10^(23)\\\\4=(mass~CO)/(28)\\\\mass~CO=112~g`